4x^2+100x-60=0

Solution for 4x^2+100x-60=0 equation:

4x^2+100x-60=0

a = 4; b = 100; c = -60;
Δ = b2-4ac
Δ = 1002-4·4·(-60)
Δ = 10960
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{10960}=\sqrt{16*685}=\sqrt{16}*\sqrt{685}=4\sqrt{685}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(100)-4\sqrt{685}}{2*4}=\frac{-100-4\sqrt{685}}{8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(100)+4\sqrt{685}}{2*4}=\frac{-100+4\sqrt{685}}{8}
$